Saili plants $4$ saplings, in a row, in her garden. The distance between two adjacent saplings is $\frac{3}{4} m .$ Find the distance between the first and the last sapling.

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Solution

From the figure, it can be observed that gaps between 1^st and last sapling $= 3$
Length of $1$ gap $= \frac{3}{4} m$
Therefore, the distance between I and IV sapling $= 3 \times \frac{3}{4} = \frac{9}{4} = 2 \frac{1}{4} m$

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Saili plants 4 saplings, in a row, in her garden. The distance between two adjacent saplings is 34 m. Find the distance between the first and the last sapling.

From the figure, it can be observed that gaps between 1st and last sapling =3Length of 1 gap =34 mTherefore, the distance between I and IV sapling =3×34=94=214 m

Saili plants $4$ saplings, in a row, in her garden. The distance between two adjacent saplings is $\frac{3}{4} m .$ Find the distance between the first and the last sapling.

From the figure, it can be observed that gaps between 1^st and last sapling $= 3$
Length of $1$ gap $= \frac{3}{4} m$
Therefore, the distance between I and IV sapling $= 3 \times \frac{3}{4} = \frac{9}{4} = 2 \frac{1}{4} m$