Question

Saket bought a new racing car and started testing the acceleration claimed by the company with uniform acceleration from 18.5 m/s to 46.1 m/s in 2.47 seconds. The distance traveled by him in this time will be-

• A. 81.9 m
• B. 49.7 m
• C. 56.2 m
• D. 79.8 m

Answer 1

The correct option is D

79.8 m

$v_i=18.5m/s$ $v_f=46.1m/s$ $t=2.47s$
$a=\frac{Changeinv}{t}$
$a=\frac{46.1\frac{m}{s}-18.5\frac{m}{s}}{2.47s}$
$a=11.2m/s^2$
$d=v_i\times t+0.5\times a\times t^2$
$d=\left(18.5m/s\right)\times \left(2.47s\right)+0.5\times \left(11.2m/s^2\right)\times (2.47s{)}^2$
$d=45.7m+34.1m$
$d=79.8m$