Salicylic acid on bromination gives:

2, 4, 6 - t r i b r o m o

salicyclic acid

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2, 4, 6 - t r i b r o m o

benzoic acid

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2, 4, 6 - t r i b r o m o

phenol

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p - b r o m o

salicylic acid

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Solution

The correct option is C $2, 4, 6 - t r i b r o m o$ phenol
Salicylic acid on reaction with bromine water form $2, 4, 6 - t r i b r o m o p h e n o l$ . This is because salicylic acid is partially activated towards eletrophilic aromatic substitution by the hydroxyl group and slightly activated by the carboxyl group.

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