Question

Saloni invest 60% of her money at the rate of 18% per annum for 4years. The remaining sum was invested at 14% per annum for 5 years. Find the sum of money she invested each time, if the difference between the simple interests earned is Rs.1520.

Answer 1

Let sum of money$=x$

money invested at $18\%$ is $60\%$ of x

$\Rightarrow \frac{6x}{10}$

Interest$=\frac{PRT}{100}=\frac{\frac{6x}{10}\times 18\times 4}{100}$

$=\frac{6\times 18\times 4x}{1000}=\frac{432x}{1000}$

Remaining sum$=\frac{4x}{10}$

Interest$=\frac{PRT}{100}=\frac{\frac{4x}{10}\times 14\times 5}{100}$

$=\frac{(4\times 14\times 5)}{100}x=\frac{280x}{1000}$

$\Rightarrow$ Difference of interest$=1520$

$\frac{432x-280x}{1000}=1520$

$152x=1520000$

$\Rightarrow x=10000$Rs.