Salt S is prepared by reacting dilute sulphuric acid with copper oxide. Identify S?

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Solution

Sulphuric acid neutralizes bases (oxides and hydroxides) to form salt and water.
So, cupric oxide reacts with sulphuric acid to form copper sulphate and water.
Salt S is prepared by reacting dilute sulphuric acid with copper oxide.
Hence, salt S is copper sulphate.
$CuO (s) + H_{2} {SO}_{4} (aq) \to {CuSO}_{4} (s) + H_{2} O (l) Copper oxide Sulphuric acid Copper sulphate Water$

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