Given : Mass of ball = 200 g = 0.2 kg, Initial speed of the ball = 10 ms−1, Final speed of the ball = 20 ms−1, Time interval = 0.5 seconds
Using work-energy theorem for the ball,
1/2 mv2 - 1/2 mu2 = Work done on the ball by the bat
=>1/2 m (v2 - u2) = W
=> 1/2 x 0.2 x ( (20)2 - (102) ) = W
=> W = 30 J
Now, Power = Work done / time interval
=> P = 30 / 0.5
=> P = 60 Watt