Sam, Peter and Roy are given 104 chocolates. If they decide to share their sweets in the ratio 10: 9 : 7, how many chocolates would Sam, Peter and Roy get respectively?
A
40, 60 and 4
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B
100, 2 and 2
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C
36, 40 and 28
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D
40, 36 and 28
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Solution
The correct option is D 40, 36 and 28 We have to divide 104 chocolates among Sam, Peter and Roy in the ratio 10 : 9 : 7. This means that Sam, Peter and Roy get (1010+9+7)th= (1026)th, (926)th and (726)th of the total respectively. i.e., Sam's share = (1026)th×104=40sweets, Peter's share = (926)th×104=36sweets Roy's share = (726)th×104=28sweets