Sam's cubicle is exactly in the shape of a cube of side 6 m. It is a closed cubicle from all the 6 surfaces. The total surface area of the cubicle ignoring the thickness is ___ $m^{2}$

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Solution

Total surface area of the cube shaped room

= 6 $a^{2}$

Given $a = 6 m$

= 6 $\times$ 36

= 216 $m^{2}$

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Sam's cubicle is exactly in the shape of a cube of side 6 m. It is a closed cubicle from all the 6 surfaces. The total surface area of the cubicle ignoring the thickness is ___m2

Total surface area of the cube shaped room = 6a2 Given a = 6 m = 6 × 36 = 216m2

Sam's cubicle is exactly in the shape of a cube of side 6 m. It is a closed cubicle from all the 6 surfaces. The total surface area of the cubicle ignoring the thickness is ___ $m^{2}$

Total surface area of the cube shaped room

= 6 $a^{2}$

Given $a = 6 m$

= 6 $\times$ 36

= 216 $m^{2}$