Sam uses lift to move from 2nd floor to 4th floor. What will be the change in his potential energy?
Take mass of Sam = 50 kg, Height of each floor 7 m and g = 10 ms $^{- 2}$ .

- 1400 J

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1400 J

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- 7000 J

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7000 J

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Solution

The correct option is D 7000 J
Given : Mass of Sam = 50 kg,
Height of each floor 7 m,
g = 10 ms $^{- 2}$

Sam is going from 2nd floor to 4th floor.
Hence, the total height travelled by Sam = height of 4th floor (h $_{2}$ ) - height of 2nd floor (h $_{1}$ )
=> (h $_{2}$ - h $_{1}$ ) = 4 x 7 - 2 x 7 = 14 m

Thus, the change in his potental energy = Final potential energy - Initial Potential Energy
= mg(h $_{2}$ - h $_{1}$ ) = 50 x 10 x 14 = 7000 J

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Question 134

A multistory building has 25 floors above the ground level each of height 5 m. it also has 3 floors in the basement each of height 5m. A lift in building moves at a rate of $\frac{1 m}{s}$ . If a man starts from 50m above the ground, how long will it take him to reach 2nd floor of the basement?

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Sam uses lift to move from 2nd floor to 4th floor. What will be the change in his potential energy? Take mass of Sam = 50 kg, Height of each floor 7 m and g = 10 ms−2.

Sam uses lift to move from 2nd floor to 4th floor. What will be the change in his potential energy?
Take mass of Sam = 50 kg, Height of each floor 7 m and g = 10 ms $^{- 2}$ .