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Standard X

Physics

Specific Heat Capacity

Same amount o...

Question

Same amount of heat energy, Q is supplied to ice at $0^{o} C$ and water at $100^{o} C$ . Choose the right option:

Mass of ice melted = Mass of water vaporised

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Mass of ice melted > Mass of water vaporised

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Mass of ice melted < Mass of water vaporised

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Solution

The correct option is D Mass of ice melted > Mass of water vaporised
Given that heat supplied during melting = heat supplied during vaporisarion
$m_{f} L_{f} = m_{v} L_{v}$
$m_{f} / m_{v} = L_{v} / L_{f}$
$= 2268 / 336$
$= 6.75$
Hence, $m_{f} > m_{v}$

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Similar questions

Q. Ice at

0^{o} C

is added to

500 g

of water at

100^{o} C

degree. Ice is continually added to the system until it has all melted and no more ice will melt. What will be the temperature of the water in the system?

Q. A piece of ice of mass

40 g

0^{o} C

is added to

200 g

of water at

50^{\circ} C

. Calculate the final temperature of water when all the ice has melted. Specific heat capacity of water =

4200 J k g^{- 1} K^{- 1}

and specific latent heat of fusion of ice =

336 \times 10^{3} J k g^{- 1}

80 g

of water at

30^{o} C

is poured on a large block of ice at

0^{o} C

. The mass of ice that melts is:

Q. A small quantity, mass

m

, of water at a temperature

θ (i n^{\circ} C)

is poured on to a large mass

M

of ice which is at its melting point. If

c

is specific heat capacity of water and

L

the latent heat of fusion of ice, then the mass of ice melted is given by

Heat is supplied at the same rate to equal masses of ice and water at the melting point (MP) of ice. Calculate the ratio of the time required to melt the ice and to bring the water to its Boiling Point. [Given that specific heat capacity of water = 4.2 J/g^oC, Specific latent heat of ice = 336 J/g]

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Same amount of heat energy, Q is supplied to ice at 0o C and water at 100o C. Choose the right option:

The correct option is D Mass of ice melted > Mass of water vaporisedGiven that heat supplied during melting = heat supplied during vaporisarion mfLf=mvLvmf/mv=Lv/Lf =2268/336 =6.75Hence, mf>mv

Same amount of heat energy, Q is supplied to ice at $0^{o} C$ and water at $100^{o} C$ . Choose the right option:

The correct option is D Mass of ice melted > Mass of water vaporised
Given that heat supplied during melting = heat supplied during vaporisarion
$m_{f} L_{f} = m_{v} L_{v}$
$m_{f} / m_{v} = L_{v} / L_{f}$
$= 2268 / 336$
$= 6.75$
Hence, $m_{f} > m_{v}$