Same current $i$ is flowing in two straight parallel conducting wires situated at distance $d$ apart. The magnetic induction at the centre between two wires will be :

z e r o

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\frac{μ_{0} i}{d}

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\frac{4 μ_{0} i}{d}

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\frac{μ_{0} i}{2 d}

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Solution

The correct option is B $z e r o$
Let the wires be in $x y$ plane.,
$_{1} = \frac{μ_{0} i}{2 π \frac{d}{2}}^k$
$_{2} = \frac{μ_{0} i}{2 π \frac{d}{2}} (-^k)$
$\to B =_{1} +_{2} = \frac{μ_{0} i}{2 π \frac{d}{2}}^k + \frac{μ_{0} i}{2 π \frac{d}{2}} (-^k) = 0$

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Same current i is flowing in two straight parallel conducting wires situated at distance d apart. The magnetic induction at the centre between two wires will be :

The correct option is B zeroLet the wires be in xy plane., →B1=μ0i2πd2^k→B2=μ0i2πd2(−^k)→B=→B1+→B2=μ0i2πd2^k+μ0i2πd2(−^k)=0

Same current $i$ is flowing in two straight parallel conducting wires situated at distance $d$ apart. The magnetic induction at the centre between two wires will be :

The correct option is B $z e r o$
Let the wires be in $x y$ plane.,
$_{1} = \frac{μ_{0} i}{2 π \frac{d}{2}}^k$
$_{2} = \frac{μ_{0} i}{2 π \frac{d}{2}} (-^k)$
$\to B =_{1} +_{2} = \frac{μ_{0} i}{2 π \frac{d}{2}}^k + \frac{μ_{0} i}{2 π \frac{d}{2}} (-^k) = 0$