Same force acts on two bodies of different masses $2 k g$ and $4 k g$ initially at rest. The ratio of times required to acquire same final velocity is:-

2 : 1

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1 : 2

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1 : 1

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4 : 16

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Solution

The correct option is A $1 : 2$
Now acceleration will be different in the two masses
They will be $\frac{F}{2} a n d \frac{F}{4}$
Let v be the same velocity attained by them starting from rest
So using v = u + a t
$V_{1} = \frac{F}{2} \times T_{1}$

$V_{2} = \frac{F}{4} \times T_{2}$

Given $v_{1} = v_{2}$
$\frac{F}{2} \times T_{1} = \frac{F}{4} \times T_{2}$

=1:2

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Same force acts on two bodies of different masses 2kg and 4kg initially at rest. The ratio of times required to acquire same final velocity is:-

The correct option is A 1:2Now acceleration will be different in the two massesThey will be F2andF4Let v be the same velocity attained by them starting from restSo using v = u + a tV1=F2×T1V2=F4×T2​​Given v1=v2F2×T1=F4×T2=1:2

Same force acts on two bodies of different masses $2 k g$ and $4 k g$ initially at rest. The ratio of times required to acquire same final velocity is:-