1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Same spring is attached with 2kg, 3kg and 1 kg blocks in three different cases as shown in the figure. If x1,x2 and x3 be the extensions in the spring in these three cases then

A
x1=0,x3>x2
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B
x2>x1>x3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
x3>x1>x2
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
D
x1>x2>x3
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
Open in App
Solution

## The correct option is B x2>x1>x3Let us find the acceleration of the system in all three cases. So, we have acceleration a=(Supporting Force-Opposing force)Total mass Thus, In (case 1) a=2g−2g4=0 ∴ T=kx1=2g⇒ x1=2gk In (case 2) a=3g−2g5=g5 ∴ T=kx2=3g+3×g5=18g5⇒ x2=18g5k In (case 3) a=2g−g3=g3 ∴ T=kx3=g−g3=2g3⇒ x3=2g3k Now, finding the ratio of x1, x2 and x3 we have x1:x2:x3=2g:3.6g:0.67g Thus, x2>x1>x3

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Problem Solving Using Newton's Laws
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program