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Stoichiometric Calculations

Sample of C...

Question

Sample of $C a C O_{3}$ of $50 %$ purity forms $0.56$ g residue. Thus, sample weighs (g) :

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Solution

$C a C O_{3} \to C a O + C O_{2}$
$0.56$ g of the residue ( $C a O$ ) corresponds to $\frac{0.56}{56} = 0.01$ moles.
This is obtained from $0.01$ moles of $C a C O_{3}$ which corresponds to $0.01$ mol $\times 100$ g/mol $\times 0.5 = 2$ g.

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