Samuel goes to the market and purchases $5$ chocolates and $7$ pastries. If the cost of $1$ chocolate is $$ x$ and the cost of $1$ pastry is $$ y$ , then find the algebraic expression for the total cost (in $$$ ) of these two items.

5 x \times 7 y

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7 x + 5 y

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5 x + 7 y

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5 x - 7 y

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Solution

The correct option is C $5 x + 7 y$
Cost of $1$ chocolate $= $ x$
$∴$ Cost of $5$ chocolates
$=$ $5 \times$ Cost of one chocolate
$= 5 \times $ x = $ 5 x$

And Cost of $1$ pastry $= $ y$
$∴$ Cost of $7$ pastries
$= 7 \times$ Cost of one pastry
$= 7 \times $ y = $ 7 y$

Total cost $=$ Cost of $5$ chocolates $+$ Cost of $7$ pastries
$= $ 5 x + $ 7 y$
$= $ (5 x + 7 y)$

The total cost of the two items that Samuel purchased would be $$ (5 x + 7 y)$ .

Therefore, option (c.) is the correct answer.

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Samuel goes to the market and purchases 5 chocolates and 7 pastries. If the cost of 1 chocolate is $x and the cost of 1 pastry is $y, then find the algebraic expression for the total cost (in $) of these two items.

Samuel goes to the market and purchases $5$ chocolates and $7$ pastries. If the cost of $1$ chocolate is $$ x$ and the cost of $1$ pastry is $$ y$ , then find the algebraic expression for the total cost (in $$$ ) of these two items.