Question

Sanjay and Sonia start from a given point and travel by car on a straight road at an average speed of $30km$ and $50km$ per hour respectively. Sanjay starts at $10am$ and Sonia starts $3$ hours later. Find the time when Sonia meets Sanjay.

Answer 1

Let the time duration for which Sanjay drove care be $t$ hours

Then according to the given condition, time duration for which Sonia drove car will be $t-3$ hours

Now, two cars starting from the same point will meet again when they have covered equal distances.

So, on equating the distance travelled by the cars, we get

$\Rightarrow 30\times \left(t\right)=50\times (t-3)$

$\Rightarrow 20\times t=150$

$\Rightarrow t=7.5hours$

$\Rightarrow t=7hours30minutes$

Hence they will meet at $10:00hours+7:30hours$

$\Rightarrow 17:30hours$

$\Rightarrow 5:30PM$