Question

Sanjay walks 7 km towards north and turns towards left and covers 3 km. Again he turns towards left and walks 11 km. How far is he from the starting point(in km)?

Answer 1

Sanjay started from A and walks 7 km north up to B, turns towards left (west) and goes 3 km to C and walks towards left (south) and walks II km and reaches point E.
Now $DA=CB=3km$
$DC=AB=7km$
$DE=11-DC=4km$
$DA=3km$
$DE=4km$
$EA=$$\sqrt{D{E}^2+D{A}^2}=\sqrt{16+9}=\sqrt{25}=5$