Santosh has x pens, and y pencils . Anjan has 3 pens less than Santosh, but thrice as many pencils. The expression for the total number of pencils and pens with Anjan is:

6x + 3y - 3

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x + 4y - 3

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x + 3y - 2

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x + 3y - 3

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Solution

The correct option is D
x + 3y - 3

Anjan has 3 pens less than Santosh => x- 3

Thrice as many pencils => 3y

Total number of pencils and pens with Anjan = x + 3y - 3

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Santosh has x pens, and y pencils . Anjan has 3 pens less than Santosh, but thrice as many pencils. The expression for the total number of pencils and pens with Anjan is:

The correct option is D x + 3y - 3 Anjan has 3 pens less than Santosh => x- 3 Thrice as many pencils => 3y Total number of pencils and pens with Anjan = x + 3y - 3

The correct option is D
x + 3y - 3

Anjan has 3 pens less than Santosh => x- 3

Thrice as many pencils => 3y

Total number of pencils and pens with Anjan = x + 3y - 3