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Question

Sanya, Aarushi, Manav and Kabir made greeting cards. Complete the table for their cards:
Whose card Length Width Perimeter Area
Sanya 10 cm 8 cm
Manav 11 cm 44 cm
Aarushi 8 cm 80 square cm
Kabir 40 cm 100 square cm

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Solution

Perimeter of Sanya's card = Sum of all its sides = 10 + 8 + 10 + 8 = 36 cm

Length of Manav's card = 11 cm
Perimeter of his card = 44 cm

We have to find the width of Manav's card.

Perimeter of card = Sum of all its sides
= 11 + 11 + sum of 2 other sides
= 22 + sum of 2 other sides

Now, sum of two other sides = 44 − 22
= 22 cm
The two other sides of the greeting cards are width.
So, width of Manav's card = 22 ÷ 2
= 11 cm

Width of Aarushi's card = 8 cm
Area of the card = 80 square cm

Now, we have to find length of the card.

Area of card = Length of card × 8 cm = 80 square cm
So, on dividing the area of card by its width, we can get its length.
Therefore, length of Aarushi's card = 80 ÷ 8
= 10 cm

Whose card Length Width Perimeter Area
Sanya 10 cm 8 cm 36 cm 80 square cm
Manav 11 cm 11 cm 44 cm 121 square cm
Aarushi 10 cm 8 cm 36 cm 80 square cm
Kabir 10 cm 10 cm 40 cm 100 square cm

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