Question

Sarang wanted to study how fast snails can move. To do this he placed four snails next to each other and marked their trails. He put a cross (x) where each snail had reached after 20 seconds.
(a) Which snail went fastest?
(b) If snail C went on at the same speed for another 10 seconds how far would it go beyond point X?
figure

Answer 1

Distance travelled by snail A = 70 mm
= (70/1000) m
= 0.07 m
Time taken = 20 s

∴ Speed of snail A = Distance travelled/Time taken
= 0.07/20
= 0.0035 m/s
Similarly,

Speed of snail B = 0.05/20
= 0.0025 m/s

Speed of snail C = 0.06/20
= 0.0030 m/s

Speed of snail D = 0.04/20
= 0.0020 m/s

(a) Snail A moved the fastest.

(b) Speed of snail C = 0.0030 m/s
Time = 10 s
Distance travelled = Speed $\times$ Time
= 0.0030 $\times$ 10
= 0.03 m

Thus, snail C would go a distance of 0.03 m or 30 mm beyond point X.