Sasha wants to cover her kitchen room $4$ m which and $8$ cm long by square tiles. If each square tile is of side $1$ m, then find the number of the required to cover the kitchen floor room.

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Solution

Area of floor $= l e n g t h \times b r e a d t h = 4 \times 8 = 32 m^{2}$
Area of tile $= 1 \times 1 = 1 m^{2}$

No of tiles = area of floor/area of one tile
$∴$ No. of tiles required $= \frac{32}{1} = 32$

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Sasha wants to cover her kitchen room 4m which and 8cm long by square tiles. If each square tile is of side 1m, then find the number of the required to cover the kitchen floor room.

Area of floor=length×breadth=4×8=32m2Area of tile=1×1=1m2No of tiles = area of floor/area of one tile∴ No. of tiles required=321=32

Sasha wants to cover her kitchen room $4$ m which and $8$ cm long by square tiles. If each square tile is of side $1$ m, then find the number of the required to cover the kitchen floor room.

Area of floor $= l e n g t h \times b r e a d t h = 4 \times 8 = 32 m^{2}$
Area of tile $= 1 \times 1 = 1 m^{2}$

No of tiles = area of floor/area of one tile
$∴$ No. of tiles required $= \frac{32}{1} = 32$