Say true or false.
If $b = 0, c < 0$ , the roots of $x^{2} + b x + c = 0$ are numerically equal and opposite in sign.

True

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False

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Solution

The correct option is A True
Applying $b = 0, c < 0$ and let $c = - p$
$x^{2} + b x + c = 0$
$x^{2} - p = 0$
$x^{2} = p$
$x = \pm \sqrt{p}$
ANSWER: Thus roots are numerically equal and opposite in sign.

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Question 7
If b = 0, c <0, is it true that the roots of $x^{2}$ + bx + c = 0 are numerically equal and opposite in sign ? Justify your answer.

a, b

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p

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x = - 8

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