Say true or false:

If $x=1$,then it is the zeros of $x^2-4x+1$.

The correct option is B: False

Given polynomial is $p\left(x\right)=x^2-4x+1$

On putting $x=1$ in the given polynomial, we have,

$p\left(1\right)=(1{)}^2-4\times 1+1$

$=1-4+1$

$=-2$

Since, the value of the given polynomial at $x=1$ is not zero,

hence, $1$ is not the zeros of the given polynomial.