Question

Say true or false.
In an $A.P$., sum of terms equidistant from the beginning and end is constant and is equal to the sum of the first and last term.

• A. True
• B. False

Answer 1

The correct option is A True

Consider mth term of an AP
$t_m=a+(m-1)d$
Now, consider (n-m)th term:
$t_{n-m}=a+(n-m-1)d$
Sum $=2a+(n-1)d$

$=a+a+(n-1)d$

$=a+l$

Therefore, it is true that Sum of the terms is equal to the sum of the first and last terms.