The quadratic polynomial x2+kx+k have equal zeroes for some odd integer k>1.
A
True
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B
False
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Solution
The correct option is B False Given, the quadratic polynomial is p(x)=x2+kx+k. Then the Discriminant (D) =k2−4k. We know that, for equal zeros/roots, D=0. =>k2−4k=0 =>k(k−4)=0 =>k=0 or k=4 Hence the quadratic polynomial can have equal zeros at =>k=0 or k=4. So, it cannot have equal zeros for any odd integer k>1.