Say true or False:
The sum of the squares of sinθ+sin(90∘−θ) and cos θ−cos(90∘−θ) is equal to 2.
True
{sinθ+sin(90∘−θ)}2+{cosθ−cos(90∘−θ)}2={sinθ+cosθ}2+{cosθ−sinθ}2 (∵ sin(90∘−θ)=cosθ andcos(90∘−θ)=sinθ)=sin2θ+cos2θ+2sinθcosθ+cos2θ+sin2θ−2sinθcosθ=2(sin2θ+cos2θ)=2(1) (As, sin2θ+cos2θ=1)=2