Question

Say true or false:

$y=4,-2,-3$ each, are the roots of $y^2+5y+6=0$

• A. True
• B. False

Answer 1

The correct option is B False

Given, $y^2+5y+6=0$
Put y = 4 in the equation,
$16+20+6=42$ Since, the remainder for the equation is not zero, hence, 4 is not the root.
Put y = -2 in the equation,
$4-10+6=0$ Since, the remainder for the equation is zero, hence, -2 is the root.
Put y = -3 in the equation,
$9-15+6=0$ Since, the remainder for the equation is zero, hence, -3 is the root.