Question

$Sb{F}_5$ reacts with $Xe{F}_4$ to form an adduct.The shapes of cation and anion in the adduct are respectively:

• A. square planar,trigonal bipyramidal
• B. T -shaped, octahedral
• C. square pyramidal, octahedral
• D. square planar,octahedral

Answer 1

The correct option is B T -shaped, octahedral

XeF${}_4$ or xenon tetrafluoride reacts with SbF${}_5$ which is a Lewis acid and forms adduct-

XeF${}_4$ + SbF${}_5$ $\to$ [XeF${}_3$]${}^{+}$[SbF${}_6$]${}^{-}$

Thus, the cation is T-shaped and the anion is octahedral.

Hence, the correct option is $\text{B}$