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Compounds of Xenon

SbF5 reacts w...

Question

$S b F_{5}$ reacts with $X e F_{4}$ to form an adduct. The shapes of cation and anion in the adduct are respectively:

square planar, trigonal bipyramidal

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T-shaped, octahedral

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square pyramidal, octahedral

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square planar, octahedral

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Solution

The correct option is B T-shaped, octahedral
$X e F_{4}$ or xenon tetrafluoride reacts with $S b F_{5}$ and forms adduct. $X e F_{4} + S b F_{5} \to [X e F_{3}]^{+} [S b F_{6}]^{-}$
Thus, the cation is T-shaped and the anion is octahedral.
Hence, the correct option is b.

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S b F_{5}

X e F_{4}

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[X e F_{3}^{+}] [{S b F_{6}}^{-}]

[X e F_{5}^{+}] [{S b F_{6}}^{-}]

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[X e F_{3}^{+}] [S b F_{6}]^{-} a n d [X e F_{5}^{+}] [S b F_{6}^{-}] .

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\to

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Diborane forms adduct with

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