Question

Sbutract as indicated:

(i) $\frac{8}{3}-\frac{5}{9}$
(ii) $4\frac{2}{5}-2\frac{1}{5}$
(iii) $5\frac{6}{7}-2\frac{2}{3}$
(iv) $4\frac{3}{4}-2\frac{1}{6}$

Answer 1

$$\begin{gathered} \left(\mathrm{i}\right)\frac{8}{3}-\frac{5}{9} \\ =\frac{8\times 3}{3\times 3}-\frac{5\times 1}{9\times 1}(\mathrm{Because}\mathrm{LCM}\mathrm{of}3\&9\mathrm{is}9) \\ =\frac{24}{9}-\frac{5}{9}=\frac{24-5}{9} \\ =\frac{19}{9} \end{gathered}$$

$$\begin{gathered} \left(\mathrm{ii}\right)4\frac{2}{5}-2\frac{1}{5}=\frac{(5\times 4)+2}{5}-\frac{(5\times 2)+1}{5} \\ =\frac{22}{5}-\frac{11}{5}=\frac{22-11}{5} \\ =\frac{11}{5} \end{gathered}$$

$$\begin{gathered} \left(\mathrm{iii}\right)5\frac{6}{7}-2\frac{2}{3}=\frac{(7\times 5)+6}{7}-\frac{(3\times 2)+2}{3} \\ =\frac{41}{7}-\frac{8}{3} \\ \frac{41\times 3}{7\times 3}-\frac{8\times 7}{3\times 7}(\mathrm{Because}\mathrm{LCM}\mathrm{of}7\&3\mathrm{is}21) \\ \frac{123}{21}-\frac{56}{21}=\frac{123-56}{21} \\ =\frac{67}{21} \end{gathered}$$

$$\begin{gathered} \left(\mathrm{iv}\right)4\frac{3}{4}-2\frac{1}{6}=\frac{(4\times 4)+3}{4}-\frac{(6\times 2)+1}{6} \\ =\frac{19}{4}-\frac{13}{6} \\ \frac{19\times 3}{4\times 3}-\frac{13\times 2}{6\times 2}(\mathrm{Because}\mathrm{LCM}\mathrm{of}4\&6\mathrm{is}12) \\ =\frac{57}{21}-\frac{26}{21} \\ =\frac{57-26}{21} \\ =\frac{31}{12} \end{gathered}$$