Question

Scooter of mass 120 kg is moving with a uniform velocity of 108 km per hour. The force required to stop the vehicle in 10 second is ?

Answer 1

Given,

$m=120kg$

$u=108km/h=\frac{108\times 1000}{60\times 60}=30m/s$

$t=10sec$

$v=0m/s$

From 1st equation of motion,

$v=u+at$

$0=30+10a$

$a=-\frac{30}{10}=-3m/s^2$

Resistance Force, $F=ma$

$F=-120\times 3=-360N$

The force required to stop vehicle is $360N$.