Question

${\sec }^{2}A+{\csc }^{2}A={\sec }^{2}A{\csc }^{2}A$

• A. True
• B. False

Answer 1

The correct option is A True

${sec}^{2}A+{\text{csc}}^{2}A=\frac{1}{{\cos }^{2}A}+\frac{1}{{\sin }^{2}A}$

$=\frac{{\sin }^{2}A+{\cos }^{2}A}{{\sin }^{2}A{\cos }^{2}A}$

$=\frac{1}{{\sin }^{2}A{\cos }^{2}A}$

$={\text{sec}}^{2}A{\text{csc}}^{2}A$