2 tan -1 2 -cosec 2 -1 3 -

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Properties Derived from Trigonometric Identities

2 tan -1 2 +c...

Question

${sec}^{2} ({tan}^{- 1} 2) + c o s e c^{2} ({cot}^{- 1} 3)$ =

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

{sec}^{2} ({tan}^{- 1} 2) + {cosec}^{2} ({cot}^{- 1} 3) =

$s e c^{2} [c o t^{- 1} (\frac{1}{2})] + c o s e c^{2} [t a n^{- 1} (\frac{1}{3})] =$

	Column - I		Column - II
a	x = $c o s e c^{2}$ $(c o t^{- 1} 3)$ - $s e c^{2}$ $(t a n^{- 1} 2)$	p	x = 2
b	$t a n^{- 1}$ x + $t a n^{- 1}$ $\frac{1}{y}$ = $(t a n^{- 1} 3)$ and $y^{2}$ + y - 56 = 0	q	x = 5
c	$c o s^{- 1}$ x = $t a n^{- 1}$ y and $y^{2}$ = 3	r	$x = \frac{1}{2}$
d	$s i n^{- 1}$ $(t a n \frac{π}{4})$ - $s i n^{- 1}$ $\sqrt{\frac{3}{y}}$ = $\frac{π}{6}$ and $x^{2}$ = y	s	x = - $\frac{1}{2}$

(s e c^{2} θ - 1) (1 - c o s e c^{2} θ) = - 1

x = {sec}^{2} ({tan}^{- 1} 2) + {cosec}^{2} ({cot}^{- 1} 3)

y = {tan}^{- 1} \frac{\sqrt{1 + {tan}^{2} 8} - 1}{tan 8}

15 x^{2} + 4 y^{2}

Join BYJU'S Learning Program