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Question

sec2(tan1(2))+cosec2(cot1(3))=15

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Solution

sec2(tan1(2))+cosec2(cot1(3))=15
Let
tan12=θcot13=θsecθ=5cotθ=3sec2(sec15)cosecθ=10=5cosec2(cot13)=10
sec2[tan12]+cosec2[cot13]=15

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