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Question

sec2(tan12)+cosec2(cot13)=


A
5
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B
13
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C
15
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D
6
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Solution

The correct option is C 15

Let tan1 2=αtan α=2
and cot1 3=βcot β=3sec2(tan12)+cosec2(cot13)=sec2 α+cosec2 β=1+tan2 α+1+cot2 β=2+(2)2+(3)2=15.


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