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Question

sec2θ=4xy(x+y)2 is true if and only if


A

x+y0

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B

x=y,x0

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C

x =y

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D

x0,y0

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Solution

The correct option is B

x=y,x0


x=y,x0

We have:

sec2θ=4xy(x+y)2

4xy(x+y)21[sec2θ1]

4xy(x+y)2

4xyx2+y2+2xy

2xyx2+y2

(xy)20

(xy)0

x=y

For x =0, sec2θ will not be defined,

x0

x=y


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