Sec 50 x Sin40+ Cos40 x Cosec5

Open in App

Solution

Suggest Corrections

Similar questions

$\frac{s i n 70^{\circ} + c o s 40^{\circ}}{c o s 70^{\circ} + s i n 40^{\circ}} =$

cos130° cos40°+ sin130° sin40° is

1) Sin(40+A)cos(10+A)-cos(40+A)sin(10+A)

s e c 50^{\circ} s i n 40^{\circ} + c o s 40^{\circ} c o s e c 50^{\circ}

cos130° cos40° + sin130° sin40° is equal to

Join BYJU'S Learning Program

Related Videos

Graphs of Trigonometric Functions

MATHEMATICS

Watch in App

Explore more

Join BYJU'S Learning Program