(sec A + tan A) (1 − sin A) =

(a) sec A
(b) sin A
(c) cosec A
(d) cos A

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Solution

The given expression is .

Simplifying the given expression, we have

Therefore, the correct option is (d).

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Similar questions

Choose the correct option. Justify your choice.

(i) $9 {sec}^{2} A - 9 {tan}^{2} A =$

(A) $1$

(B) $9$

(D) $0$

(ii) $(1 + tan θ + sec θ) (1 + cot θ - cosec θ)$

(A) $0$

(B) $1$

(D) $- 1$

(iii) $(sec A + tan A) (1 - sin A) =$

(A) $sec A$

(B) $sin A$

(D) $cos A$

(iv) $\frac{1 + {tan}^{2} A}{1 + {cot}^{2} A} =$

(A) ${sec}^{2} A$

(B) $- 1$

(D) ${tan}^{2} A$

The expression $E = \frac{c o t A - c o s A}{c o t A + c o s A}$ is the same in value in which of the following expressions?

(sec A + tan A) (1 - sin A) =

\frac{c o s s A c o s e c A - s i n A s e c A}{c o s A + s i n A}

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