$(s e c A + t a n A) (1 - s i n A) = ?$

(a) sin A (b) cos A (c) sec A (d) cosec A

Open in App

Solution

$(s e c A + t a n A) (1 - s i n A)$

$= (\frac{1}{c o s A} + \frac{s i n A}{c o s A}) (1 - s i n A)$

$= [\frac{(1 + s i n A)}{c o s A}] (1 - s i n A)$

$= \frac{(1 + s i n A) (1 - s i n A)}{c o s A}$

$= \frac{(1 - s i n^{2} A)}{c o s A}$

$= \frac{(c o s^{2} A)}{c o s A}$

$= c o s A$

Suggest Corrections

Similar questions

(sec A + tan A) (1 - sin A) =

(s e c A + t a n A) (1 - s i n A)

[(sec A + tan A) (1 - sin A)] on simplification gives:

Join BYJU'S Learning Program