The correct option is A sec A (sec A + tan A) (1 sin A) = (1/cos A+ sin A/cos A) (1 sin A) = (1 + sin A/cos A) (1 sin A) = (1 sin^2A)/cos A ...

You visited us 4 times! Enjoying our articles? Unlock Full Access!

Trigonometric Identities

A+tan A1-sin ...

Question

(sec A + tan A) (1 - sin A) =

sec A

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

sin A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

cosec A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

cos A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is
D

cos A

$(s e c A + t a n A) (1 - s i n A)$
$= (\frac{1}{c o s A} + \frac{s i n A}{c o s A}) (1 - s i n A)$
$= (\frac{1 + s i n A}{c o s A}) (1 - s i n A)$
$= \frac{(1 - s i n^{2} A)}{c o s A}$
$= \frac{c o s^{2} A}{c o s A} = c o s A$

Suggest Corrections

Similar questions

$(s e c A + t a n A) (1 - s i n A) = ?$

(a) sin A (b) cos A (c) sec A (d) cosec A

(s e c A + t a n A) (1 - s i n A)

[(sec A + tan A) (1 - sin A)] on simplification gives:

Join BYJU'S Learning Program