Question

$\sec \theta -\tan \theta =8$

Then $\sec \theta +\tan \theta =?$

Answer 1

$\sec \theta -\tan \theta =8$

${\sec }^2\theta -{\tan }^2\theta =1$

$(\sec \theta -\tan \theta )$$(\sec \theta +\tan \theta )=1$

$\sec \theta +\tan \theta =\frac{1}{8}$