Question

Second ionization potential $\left(I{P}_2\right)$ of Calcium is lower than $I{P}_2$ of Potassium.
State whether the given statement is true or false.

• A. True
• B. False

Answer 1

The correct option is A True

After removing one electron from calcium and potassium electronic configurations are as follows,$1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^1$ and $1s^{2}2s^{2}2p^{6}3s^{2}3p^6$ respectively. Hence to remove one more electron that is second ionization potential from calcium is easier than potassium because potassium got noble and stable configuration after the first I.P. Hence the second I.P of calcium is less than that of potassium.