Second ionization potential of $L i, B e, B$ is in the order:

L i > B e > B

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L i > B > B e

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N e > L i > B

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B > B e > C

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Solution

The correct option is B $L i > B > B e$
Due to penetration effect and stable inert gas configuration. The order of $I I^{n d}$ ionisation energy order is $L i > B > B e$ .

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