Question

Seed mixture X is 40 percent rye grass and 60 percent blue grass by weight; seed mixture Y is 25 percent rye grass and 75 percent fescue. If a mixture of X and Y contains 30 percent rye grass, what percent of the weight of the mixture is X?

• A. 10%
• B. $33\frac{1}{3}$%
• C. 40%
• D. 50%
• E. $66\frac{2}{3}$%

Answer 1

The correct option is B $33\frac{1}{3}$%

Seed $X$ contains $40\%$ rye grass and $60\%$ blue grass.

Seed $Y$ contains $25\%$ rye grass and $75\%$ blue grass.

Seed $X$ and $Y$ contains $30\%$ rye grass

$5\%:10\%=1:2Sumofratio=1+2=3$

$\therefore$ % of weight of the mixture $X$=$\frac{1}{3}\times 100\%=33\frac{1}{3}\%$