Question

Seg NQ is the bisector of $\angle N$ of $△MNP$. If $MN=5,PN=7,MQ=2.5$ then find QP.

Answer 1

REF.image

$In△$ MNP,NQ is bisector

of $\angle$N.(Given)

$\frac{NM}{NP}=\frac{MQ}{QP}$

[property of angle bisector of triangle]

$\therefore \frac{5}{7}=\frac{2.5}{QP}$

$\Rightarrow 5.QP=2.5\times 7$

$\Rightarrow QP=\frac{2.5\times 7}{5}$

$\Rightarrow QP=0.5\times 7$

$\Rightarrow QP=3.5$

$\therefore$ $QP=3.5$ units.