Question

Select 1 for True and 0 for False.

When $Fe\left(s\right)$ is dissolved in aqueous $HCl$ in a closed vessel, the work done is 0.

Answer 1

When $Fe\left(s\right)$ is dissolved in aqueous $HCl$ in a closed vessel, the work done is 0.
$Fe+2HCl\to FeC{l}_2+H_2\uparrow$
Since, the vessel is closed, there is no contraction or expansion.
Thus, there is no volume change.
Hence, the work done is $P\Delta V=P\times 0=0$