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Question

Select a suitable identity and expand the following products:
(3k+4l)(3k+4l)

A
9k2+24kl+16l2
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B
9k224kl+16l2
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C
9k2+24kl16l2
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D
None of these
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Solution

The correct option is A 9k2+24kl+16l2
We multiply the given polynomials (3k+4l)(3k+4l) as shown below:

(3k+4l)(3k+4l)=(3k+4l)2=(3k)2+(4l)2+(2×3k×4l)((a+b)2=a2+b2+2ab)=9k2+16l2+24kl

Hence, (3k+4l)(3k+4l)=9k2+24kl+16l2.

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