Select correct statements:

Bond order of:

H e_{2}

is zero

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H e_{2}^{+}

0.5

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H e_{2}^{2 +}

1.0

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B e_{2}

is zero

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Solution

The correct options are
A $H e_{2}$ is zero
B $B e_{2}$ is zero
C $H e_{2}^{+}$ is $0.5$
D $H e_{2}^{2 +}$ is $1.0$
Bond order $= \frac{n o . o f b o n d i n g e l e c t r o n - n o o f a n t i b o n d i n g e l e c t r o n}{2}$ .

$H e_{2}$ B.O. $= 1 / 2 (2 - 2) = 0$

$H e_{2}^{+}$ B.O. $= 1 / 2 (2 - 1) = 0.5$
$H e_{2}^{+ 2}$ B.O. $= 1 / 2 (2 - 0) = 1$
$B e_{2}$ B.O. $= 1 / 2 (4 - 4) = 0$

So, all those options are correct.

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Similar questions

H e_{2}, H e_{2}^{+}

H e_{2}^{2 +}

H e_{2}

H e_{2}

Question 19

Which of the following statement is not correct from the view point molecular orbital theory?

(a) $B e_{2}$ is not a stable molecule

(b) $H e_{2}$ is not stable but $H e_{2}^{+}$ is expected to exist.

(d) The order of energies of molecular orbitals in $N_{2}$ molecule is

$σ 2 s < σ^{*} 2 s < σ 2 p_{z} < (π^{*} 2 p_{x} ≃ π^{*} 2 p_{y}) < σ^{*} 2 p_{z}$

H e_{2}

H e_{2}

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