Select from the following equations describing the set of all points (x,y) in the coordinate plane that are at a distance of √3 from the point (2,−5).
A
(x−2)2+(y−5)2=3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(x−2)2+(y+5)2=3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
(x+2)2+(y+5)2=3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(x+2)2−(y−5)2=3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
(x−2)2−(y+5)2=3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B(x−2)2+(y+5)2=3 Given that point (x,y) is at a distance of √3 from the point (2,−5) So we have √(x−2)2+(y+5)2=√3 On squaring both sides, we get