The correct option is D Transition elements cannot form complexes.
d-block elements have high tendency to form complexes because of their small size, high effective nuclear charge and availability of vacant d-orbital. Therefore they accept lone pair of electrons of ligands in their vacant dorbitals and forms complexes.
As we know, magnetic moment =√n(n+2), where n is no. of unpaired electron.
So Cu (II) is paramagnetic as it has one unpaired electron.
Ionisation energies of 5d-elements are greater than those of 3d and 4d elements because of high nuclear charge as they have almost same radius due to lanthanide contration.
[Ti(H2O)6]3+ is coloured because here Ti3+ ion has unpaired electrons while in other complex the central metal ion is Sc3+ does not contain unpaired electrons hence it is colourless.